6[4z+2]=3[8z+4]

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Solution for 6[4z+2]=3[8z+4] equation:


Simplifying
6[4z + 2] = 3[8z + 4]

Reorder the terms:
6[2 + 4z] = 3[8z + 4]
[2 * 6 + 4z * 6] = 3[8z + 4]
[12 + 24z] = 3[8z + 4]

Reorder the terms:
12 + 24z = 3[4 + 8z]
12 + 24z = [4 * 3 + 8z * 3]
12 + 24z = [12 + 24z]

Add '-12' to each side of the equation.
12 + -12 + 24z = 12 + -12 + 24z

Combine like terms: 12 + -12 = 0
0 + 24z = 12 + -12 + 24z
24z = 12 + -12 + 24z

Combine like terms: 12 + -12 = 0
24z = 0 + 24z
24z = 24z

Add '-24z' to each side of the equation.
24z + -24z = 24z + -24z

Combine like terms: 24z + -24z = 0
0 = 24z + -24z

Combine like terms: 24z + -24z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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